I know that the first part of the formula would be BaOH + HBr but I do not know what the product would be since HBr is one thing. I do not know what to do at this point. Please help. Thank you!
Ba^2+ + OH^- + H^+ + Br^- = Ba^2+ + Br^- + H2O
Ba^2+ + 2OH^- + 2H^+ + 2Br^- ==> Ba^2+ + 2Br^- + 2H2O as the complete ionic equation. You can convert this to the NET ionic equation by canceling ions common to both sides; for example, Ba^2+ and Br^- appear on both sides so cancel them. That leaves
2OH^- + 2H^+ ==> 2H2O or
OH^-(aq) + H^+(aq) ==> H2O(l)
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