Write the formula for a complex formed between Ni 2+ and CN–, with a coordination number of 4.
I am having trouble with these problem because I don’t really understand what coordination numbers are. I know that Ni is 2+ and I believe that NH3 is 1-, but I don’t understand how to make the coordination number 5.
Thank you so much.
Basically, coordination number in complex ion formation is the number of atoms bound to the central atom. So if you want Ni^2+ and CN^- with coordination number of 4 you write [Ni(CN)4]^2- . The 2- charge is figures just like oxidation numbers; i.e., Ni ion is ^2+ and 4 CN ions at -1 each is -4. Then +2 + (-4) = -2.
You’re right that Ni^2+ is 2+ but NH3 is zero. All compounds are neutral; Ni is 2+ because that’s the charge on the ion.
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