Na2CO3(aq) + 2 HNO3(aq) –> 2NaNO3(aq) + H2O(l)
then, in the reaction above, what mass (in grams) of carbon dioxide (CO2) is formed?
2. Using the coefficients in the balanced equation, convert moles Na2CO3 to moles HNO3.
3. Now convert moles HNO3 to volume. M = moles/L. YOu have M and moles, solve for L, then convert to mL.
4. For g CO2, step 1 and 2 are the same. Convert mols CO2 to grams. g = mols x molar mass.
so for this one,
1 – it would be 0.108 x 35.7 = 3.86 moles of Na2CO3
2 – 2.86 moles Na2CO3 / 2 Moles HNO3 = 1.93 Moles HNO3.
3 – 1.93 Moles HNO3 x 0.150 M HNO3 = 0.290 L which would equal 290 mL. Is this the final solution?
4 – I need help with this one. I know the molar mass of CO2 is 44. How do i find the moles? (I know this is probably so simple I just can’t focus)
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