The titration of 25.0 mL of an unknown concentration H2SO4 solution requires 83.6 mL of 0.12 M LiOH

solution. What is the concentration of the H2SO4 solution (in M)?

solution. What is the concentration of the H2SO4 solution (in M)?

A) 0.40 M B) 0.10 M C) 0.20 M D) 0.25 M E) 0.36 M

The answer is supposedly C, but I got A. What am I doing wrong? I used the formula M1V1=M2V2 and got .250Lx=.836*0.12M.

2 Answers

M1V1 = M2V2

Where,

M1 = x

V1= 0.0250L

M2 = 0.12M

V2 = 0.0836L

Substitute in the given values like so;

Where,

M1 = x

V1= 0.0250L

M2 = 0.12M

V2 = 0.0836L

Substitute in the given values like so;

0.0250M1 = (0.12M)(0.0836L)

0.0250M1 = 0.010032mol

Divide both sides of the equation by the coefficient in front of M1 to solve for it;

M1 = 0.010032mol / 0.0250L

M1 = 0.40128M

So M1 = 0.40M

Please login or Register to submit your answer