# The energies, E, for the first few states of an unknown element are shown here in

QuestionsCategory: ChemistryThe energies, E, for the first few states of an unknown element are shown here in
The energies, E, for the first few states of an unknown element are shown here in arbitrary units:

n= 1, E=-21
n=2, E=-9
n=3, E=-4
n=4, E=-3
…,…
infinity, 0

A gaseous sample of this element is bombarded by photons of various energies (in these same units). Match each photon to the result of its absorption (or lack thereof) by an n=1 electron.

Photon/Energy:
A/21
B/17
C/15
D/12

n=1 to n=2
n=1 to n=3
n=1 to n=4
electron ejected
not absorbed

I think the A/21 is electron ejected, but I don’t know how to figure the rest…

If I could draw a diagram but I can’t. Let me try to use periods as spaces.
E = k/N2

…..1…..2…..3…..4…..inf
E = -21…-9….-4….-3……0

In going from n = 1 to n = 2 we have dE = 13
Going from 1 to 3 we have dE = 17
Going from 1 to 4 we have dE = 18
Going form 1 to inf we have dE = 21
Match them up.
A is 21 so that must be the one ejected; i.e., ionized.
B is 17 so that must be 1 to 3
C and D are not absorbed.

Check my thinking

A= ejected
B=1->3
C=not absorbed
D=1->2

A= ejected
B=1-3
C= not absorbed
D=1-2

Name the following compounds:

CH3COONa

(NH4)2SO4

Mg(H2PO4)2