For the following reaction KClO2->KCl O2 assign oxidation states to each element

QuestionsCategory: ChemistryFor the following reaction KClO2->KCl O2 assign oxidation states to each element
Lisa Howell asked 5 months ago
For the following reaction
KClO2->KCl+O2
assign oxidation states to each element on each side of the equation.

Reactants
K=?
Cl=?
O=?

Which element is reduced?

I got K=5, Cl=-1, and O=-4 . The element that reduced is K, but its says its wrong. Help, Please!

1 Answers
Lisa Howell answered 5 months ago
If you intended KClO2 (and not KClO3), here is he scoop.
K is +1. It’s ALWAYS +1 because it’s in group I of the periodic table. Cl is +3 on the left (remember all compounds are 0 so K + Cl + 2O = 0; therefore, 1 + ? + 2*-2 = 0. That makes Cl +3) and O is -2 for EACH oxygen and as you have it as -4 for the total. USUALLY, you want oxidation states for EACH atom. On the right K is +1, Cl is -1 and O2 is 0.
What is reduced? Reduction is the gain of electrons.
So Cl goes from +3 on the left to -1 on the right or gain of 4 e for each Cl.
O goes from -4 total on the left to 0 on the right or loss of 4e.
So Cl is reduced and O is oxidized.
It is important that you know the rules. Here they are.
http://www.chemteam.info/Redox/Redox-Rules.html

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