Questions › Category: Math › Find the area of the region enclosed between y=2sin(x) and y=3cos(x) from x=0 to 0 Vote Up Vote Down Fred Burton asked 5 months ago Find the area of the region enclosed between y=2sin(x) and y=3cos(x) from x=0 to x=0.7π. Hint: Notice that this region consists of two parts. Please login or Register to submit your answer Username or Email Address Password Remember Me